Grade 5 Theory Exam

For piano students of Tony O’Brien Home. Exam Structure. Learning Pathway. Exam Topics.

1

2

First count up the number of crotchets (or quavers) (or minims) in the first bar.  With rests, this comes to 7 crotchets (or 14 quavers) (or 3.5 minims).  A time signature based on quavers (1/8th notes) can be ruled out as 14 is not divisible by 3 - i.e. it’s  not compound time.   A time signature based on minims can also be ruled out because there is not a whole number minims in the bar.


The first bar then has an irregular time signature of 7/4. The only irregular time signatures you will be expected to know are  5/4 , 7/4, 5/8 and 7/8

Count up the whole number of crotchets, quavers and minims in the second bar.

There are 6 whole crotchets , 3 whole minims and 12 whole quavers.

While 12/8 could be a possibility there is nothing to indicate compound time based  on  j  - there are no groups of 3 quavers etc - the unit of beat is longer then a j


So is the time signature 6/4 or 3/2 ?  If 3/2 this would indicate “simple” time of 3 beats in the bar, and if this were the case, the tie-ing of notes in the second and third bars would be different to indicate more clearly the 3 beats in the bar - e.g. the tie of the third bar would be written as a tie between two minim notes.  The way notes have been tied suggest compound “two” time of

6/4 = as 2 x d